What are the odds of this hand?

I was playing texas hold em the other night, and on one of the hands the first four cards were red 9, black 8, red 7, and black six, that exact order, and all were different suits. It got me wondering, what are the odds of drawing that? and drawing any 4 card chaining combo in that color order?

Any 4-card straight alternating BRBR going from high to low = 10(2^4) / (52 P 4) = 1 in 40609
High-to-low OR low-to-high = [7(4 * 2^3) + 6(2^4)] / (52 P 4) = 1 in 20304

9876 BRBR = 16 / 52P4 = 1 in 406088
9876 BRBR all different suits = 2*2*1*1 / 52P4 = 1 in 1,624,350

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